From : Marty Leipzig To : All Subj : Flood Math Ä If, for no other reason to educate som

 From : Marty Leipzig
 To   : All
 Subj : Flood Math

Ä If, for no other reason to educate some and irritate others,
     what follows is a mathematical treatise on the impossibility of a
     Biblical Great Flood...

     In order to flood the Earth to the Biblical depth of "10
     cubits" above the highest mountains of the Earth; you would
     need some 4.427 billion cubic kilometers of water. The mass of
     this water would be 4.427 x 10^21 kilograms. The current amount
     of water in the Earth's hydrosphere is only 1.37 billion cubic
     kilometers. So, where did the other 2 hydrospheres full of
     water come from? It could not come from water vapor (or clouds)
     because the atmospheric pressure would be 842 times greater
     than it is now. Further, the latent heat relaeased when the
     vapor condenses into liquid would be enough to raise the
     temperature of the Earth's atmosphere to 3,570 C (6,458 F).

     Someone once suggested that a "Vapor Canopy" covered the Earth,
     and this is where all that water came from. Not so at all. What
     would keep that water in orbit above the Earth? This niggling
     little property called gravity would cause it to fall. Why
     should that take 40 days and 40 nights?  Further, this mass of
     water (some 4.427 X 10^21 Kg) stores a tremendous amount of
     potential energy which would be converted to kinetic energy
     when the water falls and would be converted to heat when it
     strikes the Earth. This potential energy (Ep=M*g*H; where
     M=mass of water, g=gravitational constant and H=height of water
     above the Earth's surface) could be calculated. If 4.427 x 10^21
     is divided by 40 days, it yields 1.107 x 10^20 Kg/day. If H=16,000m
     (approximately 10 miles), the released energy, per day, would
     equal 1.735 x 10^25 joules. The amount of energy the Earth
     would have to radiate per m^2/s is energy divided by surface
     area of the Earth times the number of seconds in one day; thus:
     Ep=1.735 x 10^25/(4*3.14159*((6386)^2)*86,400) =
     391,935.096 j/m^2/s.

     The Earth currently radiates 215 j/m^2/s at an average
     temperature of 280 K. Using the Stephan-Boltzmann fourth power
     law to calculate temperature increase:

     E(increase)/E(normal)=T^4(increase)/T^4(normal); so

     E(normal) = 215
     E(increase) = 391,935.096
     T(normal) = 280  (turn the crank, and...)
    ----------------------
     T(increase) = 1,800 K.

     The temperature of the Earth would have to rise 1,800 degrees.
     Further, the water level would rise an average of 14 cm.
     per minute for 40 days. In 13 minutes, the water level would be
     over 2 m. in depth. Further, water under standard pressure
     would not exist as a liquid at 1,800 K.

     So much for that flood...